Timeout fails on Windows

[gaborcsardi]

From #58:

callr::r(function() {
  message("hi")
  Sys.sleep(3)
  message("hi2")
  Sys.sleep(3)
  message("hi3")
}, timeout = 1)

[gaborcsardi]

Reproduce without callr:

system.time(processx::run(file.path(R.home("bin"), "R"), c("-q", "-e", "Sys.sleep(10)"), timeout = 1))

[gaborcsardi]

So, the problem is that callr starts R.exe on Windows, and this starts another R process, RTerm.exe I think.

processx/callr kills the R.exe process, but not the other RTerm.exe process, and probably because we are reading output from the Rterm.exe process (the file objects are passed to it), processx::run (and thus callr::r) keeps running.

The solution would be to start Rterm.exe directly, instead or R.exe, I think. That seems to work just fine, and needs to be fixed in callr.

[gaborcsardi]

This was callr specific, see r-lib/callr#34