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Type sometimes not inferred for argument when using --disallow-untyped-calls #9509

@JukkaL

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@JukkaL

The reveal_type in the example below produces no output, since the expression is not type checked:

# mypy: disallow-untyped-calls

def f(x):
    pass

y = 1
f(reveal_type(y))  # No output!

I think that this may also result in crashes, at least when calculating code stats.

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