enum increments `(*=1)` and `(<<=0)` work as `(+=1)`

[Daniel-Cortez]

Issue description:

enum (*= 1)
{
	EnumItem1 = 1,
	EnumItem2,
	EnumItem3,
	EnumItem4,
};

main()
{
	printf("EnumItem1: %d", EnumItem1);
	printf("EnumItem2: %d", EnumItem2);
	printf("EnumItem3: %d", EnumItem3);
	printf("EnumItem4: %d", EnumItem4);
}

Normally all enumeration elements in this example should be equal to 1, but when executing this code, it prints the following:

EnumItem1: 1
EnumItem2: 2
EnumItem3: 3
EnumItem4: 4

The same happens if increment *= 1 is replaced with <<= 0 - it's as if no increment was specified at all, so the default increment (+= 1) takes place.

Minimal complete verifiable example (MCVE):

See above.

Workspace Information:

• Compiler version: 3.10.10, 3.2.3664
• Command line arguments provided (or sampctl version):
• Operating System:

[stale]

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