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BugNeeds TriageIssue that has not been reviewed by a pandas team memberIssue that has not been reviewed by a pandas team member
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freq = pd.offsets.CustomBusinessDay(weekmask="Mon Wed Fri")
per = pd.Period("2023-04-06", freq=freq)
>>> freq.is_on_offset(per.to_timestamp())
False
>>> per
Period('2023-04-06', 'C')
The link between DateOffset and Period is a footgun. In this case, the Period machinery sees this CustomBusinessDay and doesn't distinguish between it and BusinessDay (of which CBDay is a subclass).
Probably should raise on CustomBusinessDay.
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BugNeeds TriageIssue that has not been reviewed by a pandas team memberIssue that has not been reviewed by a pandas team member