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Help WantedYou can do thisYou can do thisPossible ImprovementThe current behavior isn't wrong, but it's possible to see that it might be better in some casesThe current behavior isn't wrong, but it's possible to see that it might be better in some cases
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Description
π Search Terms
array inference, type inference, ArrayLike, lodash compact, _.compact
π Version & Regression Information
- This changed between versions 4.9.5 and 5.0.4
β― Playground Link
π» Code
type MyType<T extends unknown> = {
myKey: T;
myFunction: (arg1: T) => void;
};
const generate = (): Array<MyType<string>> => {
return Array.from({ length: 5 }).map<MyType<string>>((_, index) => {
return {
myKey: `${index}`,
myFunction: (arg1) => {
return;
},
};
});
};
const arrayLikeInferenceFunction = <T extends unknown>(
arr: ArrayLike<T | null | undefined | false | "" | 0> | null | undefined
): T[] => {
return [];
};
const arrayLikeInference = arrayLikeInferenceFunction([
{ myKey: "123", myFunction: (value) => {} }, // value is correctly inferred as string
true && { myKey: "456", myFunction: (value) => {} },
false && { myKey: "456", myFunction: (value) => {} },
...generate(),
// type inference of myFunction is lost
true && { myKey: "456", myFunction: (value) => {} }, // value is inferred as any
false && { myKey: "456", myFunction: (value) => {} },
{ myKey: "456", myFunction: (value) => {} },
]);
const arrayInferenceFunction = <T extends unknown>(
arr: Array<T | null | undefined | false | "" | 0> | null | undefined
): T[] => {
return [];
};
const arrayInference = arrayInferenceFunction([
{ myKey: "123", myFunction: (value) => {} }, // value is correctly inferred as string
true && { myKey: "456", myFunction: (value) => {} },
false && { myKey: "456", myFunction: (value) => {} },
...generate(),
// type inference of myFunction is kept
true && { myKey: "456", myFunction: (value) => {} }, // value is correctly inferred as string
false && { myKey: "456", myFunction: (value) => {} },
{ myKey: "456", myFunction: (value) => {} },
]);
π Actual behavior
The typings of the arguments of myFunction
are lost after the array spread when using ArrayLike
. When using Array
, the type inference is kept.
π Expected behavior
The arguments of myFunction
should be inferred as string
Additional information about the issue
I have opened a similar issue in the DefinitelyTyped repository for the lodash typings and they suggested opening an issue in this repository. DefinitelyTyped/DefinitelyTyped#69410
The issue originated from using lodash.compact()
with code similar to the code below:
import _ from "lodash";
type MyType<T extends unknown> = {
myKey: T;
myFunction: (arg1: T) => void;
};
const generate = (): Array<MyType<string>> => {
return Array.from({ length: 5 }).map<MyType<string>>((_, index) => {
return {
myKey: `${index}`,
myFunction: (arg1) => {
return;
},
};
});
};
const lodashInferred = _.compact([
{ myKey: "123", myFunction: (value) => {} }, // infers value as string
true && { myKey: "456", myFunction: (value) => {} },
false && { myKey: "456", myFunction: (value) => {} },
...generate(),
{ myKey: "123", myFunction: (value) => {} }, // infers value as any
true && { myKey: "456", myFunction: (value) => {} },
false && { myKey: "456", myFunction: (value) => {} },
]);
Sam-Persoon
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Help WantedYou can do thisYou can do thisPossible ImprovementThe current behavior isn't wrong, but it's possible to see that it might be better in some casesThe current behavior isn't wrong, but it's possible to see that it might be better in some cases