Description
Bugzilla Link | 39920 |
Resolution | FIXED |
Resolved on | May 09, 2019 11:14 |
Version | trunk |
OS | Windows NT |
Blocks | #35132 |
CC | @adibiagio,@topperc,@RKSimon,@rotateright |
Fixed by commit(s) | r360360 |
Extended Description
I think we should use HADDPS for the first reduction step of this on Intel CPUs
define fastcc i32 @pairwise_reduction4i32(<4 x i32> %rdx, i32 %f1) {
%rdx.shuf.1.0 = shufflevector <4 x i32> %rdx, <4 x i32> undef,<4 x i32> <i32 0, i32 2, i32 undef, i32 undef>
%rdx.shuf.1.1 = shufflevector <4 x i32> %rdx, <4 x i32> undef,<4 x i32> <i32 1, i32 3, i32 undef, i32 undef>
%bin.rdx8 = add <4 x i32> %rdx.shuf.1.0, %rdx.shuf.1.1
%rdx.shuf.2.0 = shufflevector <4 x i32> %bin.rdx8, <4 x i32> undef,<4 x i32> <i32 0, i32 undef, i32 undef, i32 undef>
%rdx.shuf.2.1 = shufflevector <4 x i32> %bin.rdx8, <4 x i32> undef,<4 x i32> <i32 1, i32 undef, i32 undef, i32 undef>
%bin.rdx9 = add <4 x i32> %rdx.shuf.2.0, %rdx.shuf.2.1
%r = extractelement <4 x i32> %bin.rdx9, i32 0
ret i32 %r
}
This is the assembly we get on sse4.1
pshufd $232, %xmm0, %xmm1 # xmm1 = xmm0[0,2,2,3]
pshufd $237, %xmm0, %xmm0 # xmm0 = xmm0[1,3,2,3]
paddd %xmm1, %xmm0
pshufd $229, %xmm0, %xmm1 # xmm1 = xmm0[1,1,2,3]
paddd %xmm0, %xmm1
movd %xmm1, %eax
retq
PHADDD uses 2 shuffles internally on Intel CPus, but as you can see the assembly we emitted also uses 2 shuffles. So I don't think we saved anything by avoiding PHADDD.