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Handle array as return variable using the lpython decorator #1891
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1b7ff7b
Handle array as return variable using the lpython decorator
Thirumalai-Shaktivel 79ef818
Use function arguments name
Thirumalai-Shaktivel 0d4aa85
Fix heap corruption
Thirumalai-Shaktivel 4996cf4
Register a test
Thirumalai-Shaktivel b0cdbde
Create an array using an API
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,19 @@ | ||
| from numpy import array | ||
| from lpython import i32, f64, lpython, TypeVar | ||
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| n = TypeVar("n") | ||
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| @lpython | ||
| def multiply(n: i32, x: f64[:]) -> f64[n]: | ||
| i: i32 | ||
| for i in range(n): | ||
| x[i] *= 5.0 | ||
| return x | ||
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| def test(): | ||
| size: i32 = 5 | ||
| x: f64[5] = array([11.0, 12.0, 13.0, 14.0, 15.0]) | ||
| y: f64[5] = (multiply(size, x)) | ||
| assert y[2] == 65. | ||
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| test() | ||
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Here is the generated C code for the above function:
Here, I think the second for loop iteration should access the
xvariable instead of_lpython_return_variable. I need to investigate more about this.There was a problem hiding this comment.
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The second loop seems to copy
xinto_lpython_return_variable, which seems correct: