Alternative route syntax

[rauchg]

To avoid routes that grow too much horizontally, and to make it easier to visualize / add / remove middleware:

app.get('/woot')
.use(express.compress())
.use(user.load())
.use(function(req, res, next){
  res.send(200);
});

[rauchg]

Also to easily introduce conditional middleware.

[rauchg]

var route = app.get('/');

if ('production' == env) {
  route.use(express.auth());
}

route.use(function(req, res, next){
  next();
});

[tj]

we should have dumped chainable methods in 3.x, totally forgot since we dont chain, we're screwed for this ATM

[tj]

however we can still do stuff like:

app.get('/woot', express.compress())
app.get('/woot', user.load())
app.get('/woot', handler)

[jonathanong]

For my pull request, you can do:

var route = app.subroute('/')

if ('production' == env) {
  route.get(express.auth());
}

route.get(function(req, res, next){
  next();
});

[defunctzombie]

@jonathanong can we instead do

var route = app.route('/');

Or is the route method call already taken? No point in calling it a subroute. This would be quite nice actually for RESTFUL apis that repeat routes but change method names.

[jonathanong]

yeah i tried doing this before, but route is taken and i didn't want to change the API around. this is what i'm doing for my own koa router: https://github.com/koajs/trie-router

i don't remember what .route does, but if we can get rid of it, i'm +1 for app.route(path)[verb](middleware)

[defunctzombie]

I don't see an app.route call...maybe my font is too small or I am getting blind in my old age.

[jonathanong]

i just remember it was defined. i don't know what it was.

[defunctzombie]

There is Router.route private api
On Nov 20, 2013 8:40 PM, "Jonathan Ong" notifications@github.com wrote:

i just remember it was defined. i don't know what it was.

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