fix: handle zero case in Armstrong number check to avoid Math.log10(0…

src/main/java/com/thealgorithms/maths/Armstrong.java

@@ -21,19 +21,24 @@ public class Armstrong {
      * @return {@code true} if the given number is an Armstrong number, {@code false} otherwise
      */
     public boolean isArmstrong(int number) {
-        if (number < 0) {
-            return false; // Negative numbers cannot be Armstrong numbers
-        }
-        long sum = 0;
-        int totalDigits = (int) Math.log10(number) + 1; // get the length of the number (number of digits)
-        long originalNumber = number;
+    if (number < 0) {
+        return false; // Negative numbers cannot be Armstrong numbers
+    }
+    if (number == 0) {
+        return true; // 0 is an Armstrong number
+    }
 
-        while (originalNumber > 0) {
-            long digit = originalNumber % 10;
-            sum += (long) Math.pow(digit, totalDigits); // The digit raised to the power of total number of digits and added to the sum.
-            originalNumber /= 10;
-        }
+    long sum = 0;
+    int totalDigits = (int) Math.log10(number) + 1;
+    long originalNumber = number;
 
-        return sum == number;
+    while (originalNumber > 0) {
+        long digit = originalNumber % 10;
+        sum += (long) Math.pow(digit, totalDigits);
+        originalNumber /= 10;
     }
+
+    return sum == number;
+}
+
 }