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Binary operator '==' cannot be applied to two '[Recorded<Event<Void>>]' operands #1552

@Arcovv

Description

@Arcovv

Short description of the issue:

Binary operator '==' cannot be applied to two '[Recorded<Event>]' operands. Void isn't implement Equatable.

What actually happens:

Hi,

Recently I tried to use RxTest with ViewModel architecture in my project. But I got some wrong from Xcode, that "Binary operator '==' cannot be applied to two '[Recorded<Event>]' operands" error log.

There is my MVVM code:

protocol ProfileViewModelInputs {
  func didTapSettingButton()
}

protocol ProfileViewModelOutputs {
  var showSetting: Signal<Void> { get }
}

final class ProfileViewModel {

  let showSetting: Signal<Void>

  init() {
    showSetting = tappingSettingButtonSubject.asSignal()
  }

  fileprivate let tappingSettingButtonSubject = PublishRelay<Void>()
  func didTapSettingButton() {
    tappingSettingButtonSubject.accept(())
  }
}

And my test code:

class ProfileViewModelTests: XCTestCase {
  
  private var viewModel: ProfileViewModel!
  private var disposeBag: DisposeBag!
  private var schedule: TestScheduler!
  
  override func setUp() {
    super.setUp()
    viewModel = ProfileViewModel()
    disposeBag = DisposeBag()
    schedule = TestScheduler(initialClock: 0)
  }
  
  override func tearDown() {
    super.tearDown()
    viewModel = nil
    disposeBag = nil
    schedule = nil
  }
  
  func test_tapping_setting_button() {
    let tapObserver = schedule.createObserver(Void.self)
    viewModel.outputs.showSetting
      .debug(#function)
      .emit(to: tapObserver)
      .disposed(by: disposeBag)
    schedule.start()
    
    viewModel.inputs.didTapSettingButton()
    
    let expectedEvents = [
      next(0, ())
    ]
    let tapEvents = tapObserver.events

    XCTAssert("\(tapObserver.events)" == "\(expectedEvents)")
  }
}

In this code, I can't use tapObserver.events == expectedEvents because Void is not implemented Equatable. Only I can transform it to string. How to solve this problem?

Thanks for you help.

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