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TypeError: generate() got an unexpected keyword argument 'reorder' line 100 in Pyverilog/examples/example_graphgen.py #131

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@zhangshuaiAA9

python3 Pyverilog/examples/example_graphgen.py -t top -s top.led test.v
Generating LALR tables
WARNING: 183 shift/reduce conflicts
Traceback (most recent call last):
File "./examples/example_graphgen.py", line 107, in
main()
File "./examples/example_graphgen.py", line 100, in main
graphgen.generate(target, walk=options.walk, identical=options.identical,
TypeError: generate() got an unexpected keyword argument 'reorder'

in example_graphgen.py", line 100,

96    graphgen = VerilogGraphGenerator(options.topmodule, terms, binddict,
97                                     resolved_terms, resolved_binddict, constlist, options.outputfile)
98
99   for target in options.searchtarget:
100       graphgen.generate(target, walk=options.walk, identical=options.identical,
101                            step=options.step, reorder=options.reorder, delay=options.delay)

There is a parameter called rerorder,The problem is that the VerilogGraphGenerator class doesn't have the reorder parameter in the generate() method definition, but it is provided when called.

The following is part of the definition of VerilogGraphGenerator class in the /Pyverilog/pyverilog/dataflow/graphgen.py

26 class VerilogGraphGenerator(object):
    ..........
    ..........
57    def generate(self, signalname, identical=False, walk=True, step=1, do_reorder=False, delay=False):
        termname = util.toTermname(signalname)
        tree = self.treewalker.getTree(termname)

One of the parameters is called do_reorder

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