FEAT: 프로그래머스 카펫 - 완전탐색 #10
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아ㅏ 제가 자꾸 브랜치 분기를 이상한데서 해서 다른 파일이 딸려오네요.. 킼킼 지송쓰!!! 담부터 더 주의하겠습니다!! |
jis-kim
approved these changes
Mar 30, 2023
| // y = brownSum - x; | ||
| int brownSum = (brown - 4) / 2; | ||
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| for (int i = 0; i < 2500; i++) { |
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전 0인 경우는 존재하지 않는다고 생각해서( 이유 : yellow 가 1 이상이면 그럴 일이 없습니다) 3부터 돌아줬읍니당
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맞아요ㅋㅎㅋㅎ 사실 2500까지도 안갔어도 됐을 것 같습니다ㅎㅎㅎ 반성반성
| for (int i = 0; i < 2500; i++) { | ||
| if (i * (brownSum - i) == yellow) { | ||
| x = i; | ||
| break; |
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이거 걍 i 를 밖에서 선언하고 break 해서 그대로 써도 됐을 듯 합니다!! 하지만 이정도는 취향일지도ㅎㅎ
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지수님 처럼! 맞아여 for문안에서 return 할 생각을 못함ㅋㅋㅋ
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너비를 주고 가로세로를 구하라고 해서 가로세로를 미지수로 놓고 방정식을 이용했습니다.
노랑이 x ,y 일때 브라운이 x+2, y+2 를 가로세로로 가지게 되니까요.
변수명을 좀 거지같이 지었는데 brownSum은 갈색의 가로+세로 입니다..ㅋㅋ
