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101 changes: 101 additions & 0 deletions labs_SQL_Data_Aggregation.sql
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use Sakila ;

-- Challenge 1 --
-- You need to use SQL built-in functions to gain insights relating to the duration of movies:
-- 1.1 Determine the shortest and longest movie durations and name the values as max_duration and min_duration.
-- 1.1 Shortest and longest movie durations (max_duration and min_duration)

select max(length) as max_duration, min(length) as min_duration
from sakila.film;

-- 1.2. Express the average movie duration in hours and minutes. Don't use decimals.
-- Hint: Look for floor and round functions.
select floor(avg(length) / 60) as hours,
floor(avg(length) % 60) as minutes
FROM sakila.film;

-- 2 You need to gain insights related to rental dates:
-- 2.1 Calculate the number of days that the company has been operating.
-- Hint: To do this, use the rental table, and the DATEDIFF() function to subtract the earliest date in the rental_date column from the latest date.
select datediff((select max(rental_date) from sakila.rental), (select min(rental_date) from sakila.rental)) as operating_days;

-- 2.2 Retrieve rental information and add two additional columns to show the month and weekday of the rental. Return 20 rows of results.
select rental_id, rental_date, inventory_id, customer_id, return_date, staff_id, last_update,
date(rental_date) as rental_date_only,
month(rental_date) as rental_month,
dayname(rental_date) as weekday
from sakila.rental
limit 20;

-- 2.3 Bonus: Retrieve rental information and add an additional column called DAY_TYPE with values 'weekend' or 'workday', depending on the day of the week.
-- Hint: use a conditional expression.
select rental_id, rental_date, inventory_id, customer_id, return_date, staff_id, last_update,
case
when dayname(rental_date) in ("Monday", "Tuesday", "Wednesday", "Thursday", "Friday") then 'weekday'
when dayname(rental_date) in ("Saturday", "Sunday") then 'weekend'
end as DAY_TYPE
from sakila.rental;

-- 3. You need to ensure that customers can easily access information about the movie collection. To achieve this, retrieve the film titles and their rental duration.
-- If any rental duration value is NULL, replace it with the string 'Not Available'. Sort the results of the film title in ascending order.
-- Please note that even if there are currently no null values in the rental duration column, the query should still be written to handle such cases in the future.
-- Hint: Look for the IFNULL() function.

select title,
ifnull(cast(rental_duration as char), 'Not Available') as rental_duration
from sakila.film
order by title asc;

-- 4. Bonus: The marketing team for the movie rental company now needs to create a personalized email campaign for customers. To achieve this, you need to retrieve the
-- concatenated first and last names of customers, along with the first 3 characters of their email address, so that you can address them by their first name and use their email
-- address to send personalized recommendations. The results should be ordered by last name in ascending order to make it easier to use the data.

select concat(first_name, ' ', last_name, ' ', left(email, 3)) as email_prefix
from sakila.customer
order by last_name asc;

-- Challenge 2
-- Next, you need to analyze the films in the collection to gain some more insights. Using the film table, determine:
-- 1.1 The total number of films that have been released.
select count(*) as total_films from sakila.film;

-- 1.2 The number of films for each rating.

select rating, count(film_id) as Number_of_films
from film
group by rating
order by rating;

-- 1.3 The number of films for each rating, sorting the results in descending order of the number of films.
-- This will help you to better understand the popularity of different film ratings and adjust purchasing decisions accordingly.

select rating, count(film_id) as Number_of_films
from film
group by rating
order by Number_of_films desc;

-- Using the film table, determine:
-- 2.1 The mean film duration for each rating, and sort the results in descending order of the mean duration.
-- Round off the average lengths to two decimal places. This will help identify popular movie lengths for each category.

select rating, round(avg(length), 2) as average_lenght
from sakila.film
group by rating
order by average_lenght desc;

-- 2.2 Identify which ratings have a mean duration of over two hours in order to help select films for customers who prefer longer movies.

select rating, round(avg(length), 2) as average_lenght
from sakila.film
group by rating
having avg(length) > 120;

-- 3. Bonus: determine which last names are not repeated in the table actor.

select last_name, count(*) as repetead
from sakila.actor
group by last_name
having count(*) = 1;