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sakila_lab_2.sql

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+-- Challenge 1: Movie Duration Insights
+
+-- 1.1 Shortest and longest movie durations
+SELECT MAX(length) AS max_duration, MIN(length) AS min_duration FROM film;
+
+-- 1.2 Average movie duration in hours and minutes (no decimals)
+SELECT FLOOR(AVG(length)/60) AS avg_hours, ROUND(AVG(length)%60) AS avg_minutes FROM film;
+
+-- Challenge 1: Rental Date Insights
+
+-- 2.1 Number of days company has been operating
+SELECT DATEDIFF(MAX(rental_date), MIN(rental_date)) AS operating_days FROM rental;
+
+-- 2.2 Rental info with month and weekday (20 rows)
+SELECT rental_id, rental_date,
+       MONTHNAME(rental_date) AS rental_month,
+       DAYNAME(rental_date) AS rental_weekday
+FROM rental
+LIMIT 20;
+
+-- 2.3 BONUS: Rental info with DAY_TYPE (weekend/workday)
+SELECT rental_id, rental_date,
+       CASE
+           WHEN DAYOFWEEK(rental_date) IN (1, 7) THEN 'weekend'
+           ELSE 'workday'
+       END AS DAY_TYPE
+FROM rental
+LIMIT 20;
+
+-- Challenge 1: Film Accessibility
+
+-- Film titles and rental duration, replacing NULLs
+SELECT title,
+       IFNULL(rental_duration, 'Not Available') AS rental_duration
+FROM film
+ORDER BY title ASC;
+
+-- BONUS: Personalized email campaign
+SELECT CONCAT(first_name, ' ', last_name) AS full_name,
+       LEFT(email, 3) AS email_prefix
+FROM customer
+ORDER BY last_name ASC;
+
+-- Challenge 2: Film Collection Analysis
+
+-- 1.1 Total number of films released
+SELECT COUNT(*) AS total_films FROM film;
+
+-- 1.2 Number of films per rating
+SELECT rating, COUNT(*) AS film_count
+FROM film
+GROUP BY rating;
+
+-- 1.3 Number of films per rating, sorted descending
+SELECT rating, COUNT(*) AS film_count
+FROM film
+GROUP BY rating
+ORDER BY film_count DESC;
+
+-- 2.1 Mean film duration per rating, rounded to 2 decimals
+SELECT rating, ROUND(AVG(length), 2) AS avg_duration
+FROM film
+GROUP BY rating
+ORDER BY avg_duration DESC;
+
+-- 2.2 Ratings with mean duration over 2 hours
+SELECT rating
+FROM film
+GROUP BY rating
+HAVING AVG(length) > 120;
+
+-- BONUS: Last names not repeated in actor table
+SELECT last_name
+FROM actor
+GROUP BY last_name
+HAVING COUNT(*) = 1;