Solved Lab 3rd Edit

sql_agg_transform_new.sql

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+USE sakila;
+
+-- Determine the shortest and longest movie durations and name the values as max_duration and min_duration
+
+SELECT 
+    MAX(length) AS max_duration,
+    MIN(length) AS min_duration
+FROM film;
+
+-- 1.2. Express the average movie duration in hours and minutes. Don't use decimals
+
+SELECT FLOOR(AVG(length)/60) AS hours,
+	   MOD(ROUND(AVG(length)), 60) AS minutes
+FROM film;
+
+-- 2.1 Calculate the number of days that the company has been operating
+
+SELECT DATEDIFF(MAX(rental_date), MIN(rental_date)) AS days_operating
+FROM rental;
+
+-- Retrieve rental information and add two additional columns to show the month and weekday of the rental. Return 20 rows of results
+
+SELECT rental_id, rental_date, inventory_id, customer_id, staff_id,
+       MONTH(rental_date) AS rental_month,
+       DAYNAME(rental_date) AS rental_weekday
+FROM rental
+LIMIT 20;
+
+-- 2.3 Bonus: Retrieve rental information and add an additional column called DAY_TYPE with values 
+-- 'weekend' or 'workday', depending on the day of the week
+
+SELECT rental_id, rental_date, inventory_id, customer_id, staff_id,
+       DAYNAME(rental_date) AS rental_weekday,
+       CASE 
+           WHEN DAYOFWEEK(rental_date) IN (1,7) THEN 'weekend'
+           ELSE 'workday'
+       END AS DAY_TYPE
+FROM rental
+LIMIT 20;
+
+-- retrieve the film titles and their rental duration. If any rental duration value is NULL, replace it with the string 'Not Available'. 
+-- Sort the results of the film title in ascending order
+
+SELECT title, IFNULL(rental_duration, 'Not Available') AS rental_duration
+FROM film
+ORDER BY title ASC;
+
+-- Bonus
+
+SELECT CONCAT(first_name, ' ', last_name) AS full_name,
+       LEFT(email, 3) AS email_prefix
+FROM customer
+ORDER BY last_name ASC;
+
+-- 1.1 The total number of films that have been released.
+SELECT COUNT(*) AS total_films
+FROM film;
+
+-- 1.2 The number of films for each rating.
+SELECT rating, COUNT(*) AS num_films
+FROM film
+GROUP BY rating;
+-- 1.3 The number of films for each rating, sorting the results in descending order of the number of films
+SELECT rating, COUNT(*) AS num_films
+FROM film
+GROUP BY rating
+ORDER BY num_films DESC;
+-- The mean film duration for each rating, and sort the results in descending order of the mean duration. Round off the average lengths to two decimal places
+
+SELECT rating, ROUND(AVG(length), 2) AS avg_duration
+FROM film
+GROUP BY rating
+ORDER BY avg_duration DESC;
+
+-- 2.2 Identify which ratings have a mean duration of over two hours in order to help select films for customers who prefer longer movies
+
+SELECT rating, ROUND(AVG(length), 2) AS avg_duration
+FROM film
+GROUP BY rating
+HAVING AVG(length) > 120;
+-- Bonus: determine which last names are not repeated in the table actor
+
+SELECT last_name
+FROM actor
+GROUP BY last_name
+HAVING COUNT(*) = 1;