Lab SQL Aggregation and Transformation OK

lab_SQL_Data Aggregation _Transformation.sql

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+USE sakila;
+
+-- Challenge 1
+-- 1.1 Shortest and longest movie durations
+SELECT
+    MAX(length) AS max_duration,
+    MIN(length) AS min_duration
+FROM film;
+
+-- 1.2 Average movie duration in hours and minutes 
+SELECT
+  FLOOR(AVG(length) / 60) AS avg_hours,
+  FLOOR(AVG(length) % 60) AS avg_minutes
+FROM film;
+
+-- 2.1 Number of days that the company has been operating
+SELECT 
+  DATEDIFF(
+    MAX(rental_date),
+    MIN(rental_date)
+  ) AS operating_days
+FROM rental;
+
+-- 2.2 Month and weekday of the rental
+SELECT
+  rental_id,
+  rental_date,
+  inventory_id,
+  customer_id,
+  staff_id,
+  MONTH(rental_date) AS rental_month,
+  DAYNAME(rental_date) AS rental_weekday
+FROM rental
+LIMIT 20;
+
+-- 2.3 Bonus : 'weekend' or 'workday'
+SELECT
+  rental_id,
+  rental_date,
+  inventory_id,
+  customer_id,
+  staff_id,
+  DAYNAME(rental_date) AS rental_weekday,
+  CASE
+    WHEN DAYOFWEEK(rental_date) IN (1, 7) THEN 'weekend'  -- 1 = dimanche, 7 = samedi
+    ELSE 'workday'
+  END AS DAY_TYPE
+FROM rental
+LIMIT 20;
+
+
+-- 3
+SELECT
+  title,
+  IFNULL(CAST(rental_duration AS CHAR), 'Not Available') AS rental_duration
+FROM film
+ORDER BY title ASC;
+
+-- Bonus 
+SELECT
+  CONCAT(first_name, ' ', last_name) AS full_name,
+  LEFT(email, 3) AS email_prefix
+FROM customer
+ORDER BY last_name ASC;
+
+
+-- Challenge 2 
+-- 1.1 Total number of films 
+SELECT COUNT(*) FROM film;
+
+-- 1.2 Number of films for each rating 
+SELECT rating, COUNT(*) AS film_count
+FROM film
+GROUP BY rating
+ORDER BY rating;
+
+-- 1.3
+SELECT rating, COUNT(*) AS film_count
+FROM film
+GROUP BY rating
+ORDER BY film_count DESC;
+
+
+-- 2.1 
+SELECT
+  rating,
+  ROUND(AVG(length), 2) AS avg_duration
+FROM film
+GROUP BY rating
+ORDER BY avg_duration DESC;
+
+-- 2.2 
+SELECT
+  rating,
+  ROUND(AVG(length), 2) AS avg_duration
+FROM film
+GROUP BY rating
+HAVING AVG(length) > 120
+ORDER BY avg_duration DESC;
+
+-- 3 Bonus 
+SELECT last_name
+FROM actor
+GROUP BY last_name
+HAVING COUNT(*) = 1;
+