Function prelude associates with caller's source position #8442
Description
With a simple setup like
pub fn f() {
io::println("foo");
}
pub fn main() {
f();
}breaking in main and stepping into f yields odd behaviour in gdb. Specifically, the first step into f shows pub fn main() {, the second shows f();, and the third takes us to the proper io::println("foo");. Disassembling at each step shows the first step takes us inside f into its prelude, so obviously we're not updating the source position correctly when generating the function.