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ENH Consistent apply output when grouping with freq #12362
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Original file line number | Diff line number | Diff line change |
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@@ -4824,6 +4824,42 @@ def test_timegrouper_get_group(self): | |
result = grouped.get_group(dt) | ||
assert_frame_equal(result, expected) | ||
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def test_timegrouper_apply_return_type_series(self): | ||
# Using `apply` with the `TimeGrouper` should give the | ||
# same return type as an `apply` with a `Grouper`. | ||
# Issue #11742 | ||
df = pd.DataFrame({'date': ['10/10/2000', '11/10/2000'], | ||
'value': [10, 13]}) | ||
df_dt = df.copy() | ||
df_dt['date'] = pd.to_datetime(df_dt['date']) | ||
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||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. you can basically put on of these test examples in the whatsnew |
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def sumfunc_series(x): | ||
return pd.Series([x['value'].sum()], ('sum',)) | ||
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expected = df.groupby(pd.Grouper(key='date')).apply(sumfunc_series) | ||
result = (df_dt.groupby(pd.TimeGrouper(freq='M', key='date')) | ||
.apply(sumfunc_series)) | ||
assert_frame_equal(result.reset_index(drop=True), | ||
expected.reset_index(drop=True)) | ||
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def test_timegrouper_apply_return_type_value(self): | ||
# Using `apply` with the `TimeGrouper` should give the | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. issue number in the comment |
||
# same return type as an `apply` with a `Grouper`. | ||
# Issue #11742 | ||
df = pd.DataFrame({'date': ['10/10/2000', '11/10/2000'], | ||
'value': [10, 13]}) | ||
df_dt = df.copy() | ||
df_dt['date'] = pd.to_datetime(df_dt['date']) | ||
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def sumfunc_value(x): | ||
return x.value.sum() | ||
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expected = df.groupby(pd.Grouper(key='date')).apply(sumfunc_value) | ||
result = (df_dt.groupby(pd.TimeGrouper(freq='M', key='date')) | ||
.apply(sumfunc_value)) | ||
assert_series_equal(result.reset_index(drop=True), | ||
expected.reset_index(drop=True)) | ||
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def test_cumcount(self): | ||
df = DataFrame([['a'], ['a'], ['a'], ['b'], ['a']], columns=['A']) | ||
g = df.groupby('A') | ||
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put the issue number here as a comment