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always true | false check with TypePredicate #25316

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@Kingwl

Description

@Kingwl

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TypePredicate

Suggestion

call a function with TypePredicate with an obviously true or obviously false argument is always useless,
and that maybe get a incorrect type guard, could we check this case or another limit set?

Use Cases

Examples

interface Node { 
  //...
}
interface Identity  extends Node { 
  //...
}
interface WTFIdentity extends Identity { 
  //...
}

function isIdentity(node: Node) node is Identity {
    // ...
}

function isWTFIdentity(node: Node) node is WTFIdentity {
  // ...
}

declare const a: Identity;
declare const b: Identity | StringLiteral;
declare const c: StringLiteral;

isIdentity(a); // obviously true
isIdentity(b); // normal behavior
isIdentity(c); // obviously false
isWTFIdentity(a);  // normal behavior
isWTFIdentity(b);  // normal behavior
isWTFIdentity(c);  // obviously false

Checklist

My suggestion meets these guidelines:

  • [] This wouldn't be a breaking change in existing TypeScript / JavaScript code
  • This wouldn't change the runtime behavior of existing JavaScript code
  • This could be implemented without emitting different JS based on the types of the expressions
  • This isn't a runtime feature (e.g. new expression-level syntax)

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    Out of ScopeThis idea sits outside of the TypeScript language design constraints

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