Open
Description
| Bugzilla Link | 25627 |
| Version | unspecified |
| OS | Linux |
| Attachments | as explained |
| Reporter | LLVM Bugzilla Contributor |
| CC | @DaemonSnake |
Extended Description
If I am correct the following code should be valid c++14:
template<int j> void g() {}
int main()
{
constexpr int i = 0;
auto f = []{ g<i>(); };
return 0;
}However, clang does not compile this code.
It does compile with when capturing [=], [i] or [&].
It also compiles if the i is made static.
This is related to a stackoverflow-question:
http://stackoverflow.com/questions/33873788/how-can-i-use-a-constexpr-value-in-a-lambda
clang version:
Debian clang version 3.8.0-svn247818-1~exp1 (trunk) (based on LLVM 3.8.0)
compile command:
clang++-3.8 -std=c++14 capture_constexpr.cpp
compiler error:
capture_constexpr.cpp:11:7: error: variable 'i' cannot be implicitly captured in a lambda with no capture-default specified
g<i>();
^
capture_constexpr.cpp:7:17: note: 'i' declared here
constexpr int i = 0;
^
capture_constexpr.cpp:10:12: note: lambda expression begins here
auto f = []{ // compiles with gcc 4.9.1, not with clang 3.8
^
1 error generated.