Templated lambda invoked in compile time doesn't instantiate if declared inside templated function

[GuzevArtem]

Example below compiles fine under MSVC and GCC

template<typename>
[[nodiscard]]
constexpr auto foo() noexcept
{
    constexpr auto extract_size = []<typename argument_t>() constexpr -> int
    {
        return 1;
    };
    //return extract_size.template operator()<int>(); // works
    constexpr int result = extract_size.template operator()<int>(); // undefined function 'operator()<int>'
    return result;
}

int main() {
    return foo<void>();
}

If foo isn't templated, it compiles fine.

https://godbolt.org/z/6bj4d6zef

:10:19: error: constexpr variable 'result' must be initialized by a constant expression :10:50: note: undefined function 'operator()' cannot be used in a constant expression

[llvmbot]

@llvm/issue-subscribers-clang-frontend

Author: None (GuzevArtem)

Example below compiles fine under MSVC and GCC

template<typename>
[[nodiscard]]
constexpr auto foo() noexcept
{
    constexpr auto extract_size = []<typename argument_t>() constexpr -> int
    {
        return 1;
    };
    //return extract_size.template operator()<int>(); // works
    constexpr int result = extract_size.template operator()<int>(); // undefined function 'operator()<int>'
    return result;
}

int main() {
    return foo<void>();
}

If foo isn't templated, it compiles fine.

https://godbolt.org/z/6bj4d6zef

<source>:10:19: error: constexpr variable 'result' must be initialized by a constant expression
<source>:10:50: note: undefined function 'operator()<int>' cannot be used in a constant expression

[zyn0217]

At first glance this is likely a duplicate of #35052

[GuzevArtem]

For future readers
WA - remove explicit lambda return type
more details: #35052 (comment)