Casting from f64 to u64 does not work

[ronnuriel]

Fix error when converting between two different types
for example:
x:i16 = i16(3)
y:u16 = x

Converting i16 to u16.

[Smit-create]

You need to explicitly define the cast. The following should work fine:

def f():
    x:i16 = i16(3)
    y:u16 = u16(x)
    print(x, y)

f()

[certik]

Thanks @Smit-create, indeed the code you posted works for me in both LLVM and C backends:

$ lpython a.py 
3 3
$ lpython --backend=c a.py
3 3

@ronnuriel can you please try it out and let us know if that fixes it for you?

[ronnuriel]

The following works:
cycles_count: i64
end_cycle: i64 = i64(100)
start_cycle: i64 = i64(4)
num_iters: i64 = i64(4)

cycles_count = i64((end_cycle - start_cycle) / num_iters)

but when u64 its not:
cycles_count: u64 #THIS LINE
end_cycle: i64 = i64(100)
start_cycle: i64 = i64(4)
num_iters: i64 = i64(4)

cycles_count = u64((end_cycle - start_cycle) / num_iters)

ERROR:
|
181 | cycles_count = u64((end_cycle - start_cycle) / num_iters)
| ^^^^^^^^^^^^ ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ type mismatch ('u64' and 'f64')

[certik]

I see, casting from f64 to u64 does not work. I think that's a bug, thanks for reporting it. As a workaround until this gets fixed, this worked for me:

    cycles_count = u64(i64((end_cycle - start_cycle) / num_iters))

[Darshan4852]

x: i16 = i16(3)
y: u16

if x >= 0:
y = u16(x)
else:
y = u16(2 ** 16 - 1)

I hope it will work.