#17 - Java

Author: ASJordi

Roadmap/17 - ITERACIONES/java/asjordi.java

@@ -0,0 +1,67 @@
+import java.util.*;
+import java.util.stream.IntStream;
+import java.util.stream.Stream;
+
+public class Main {
+
+    public static void main(String[] args) {
+        printNumbers();
+        iterate();
+    }
+
+    /**
+     * EJERCICIO:
+     * Utilizando tu lenguaje, emplea 3 mecanismos diferentes para imprimir
+     * números del 1 al 10 mediante iteración.
+     */
+    static void printNumbers() {
+        // Forma 1: Usando un for
+        for (int i = 1; i <= 10 ; i++) System.out.println(i);
+
+        // Forma 2: Iterando un List con forEach
+        for (int i : Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)) System.out.println(i);
+
+        // Forma 3: Iterando un IntStream
+        IntStream.rangeClosed(1, 10).forEach(System.out::println);
+    }
+
+    /**
+     * DIFICULTAD EXTRA (opcional):
+     * Escribe el mayor número de mecanismos que posea tu lenguaje
+     * para iterar valores. ¿Eres capaz de utilizar 5? ¿Y 10?
+     */
+
+    static void iterate() {
+        List<Integer> nums = List.of(1, 2, 3, 4, 5);
+
+        for (int i = 0; i < nums.size(); i++) System.out.println(nums.get(i));
+
+        for (Integer num : nums) System.out.println(num);
+
+        nums.forEach(System.out::println);
+
+        nums.stream().forEach(n -> System.out.println(n));
+
+        int i = 0;
+        while (i < nums.size()) {
+            System.out.println(nums.get(i));
+            i++;
+        }
+
+        Iterator<Integer> iterator = nums.iterator();
+        while (iterator.hasNext()) System.out.println(iterator.next());
+
+        Iterator<Integer> it = nums.iterator();
+        it.forEachRemaining(num -> System.out.println(num));
+
+        ListIterator<Integer> listIterator = nums.listIterator();
+        while (listIterator.hasNext()) System.out.println(listIterator.next());
+
+        nums.spliterator().forEachRemaining(System.out::println);
+
+        Arrays.stream(nums.toArray()).forEach(n -> System.out.println(n));
+
+        Stream.of(nums).forEach(System.out::println);
+
+    }
+}