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spec/Section 3 -- Type System.md

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@@ -1146,9 +1146,9 @@ interface. Querying for `age` is only valid when the result of `entity` is a
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**Interfaces Implementing Interfaces**
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When defining an interface that implements another interface, the implementing
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type must define each field that is specified by the implemented interface. For
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example, the interface Resource must define the field id to implement the Node
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interface:
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interface must define each field that is specified by the implemented interface.
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For example, the interface Resource must define the field id to implement the
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Node interface:
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```raw graphql example
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interface Node {
@@ -1392,7 +1392,7 @@ type Article implements Resource {
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title: String
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}
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type Image implements Resource {
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type Photo implements Resource {
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url: String
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height: Int
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width: Int
@@ -1435,7 +1435,7 @@ Union types have the potential to be invalid if incorrectly defined.
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2. The member types of a Union type must all be Object base types; Scalar,
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Interface and Union types must not be member types of a Union. Similarly,
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wrapping types must not be member types of a Union.
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3. An union type may declare that it implements one or more unique interfaces.
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3. A union type may declare that it implements one or more unique interfaces.
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4. Each member of a union must be a super-set of all union-implemented
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interfaces:
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1. Let this union type be {implementingType}.

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