fix: A new feature for NDArray.max #1091
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RayWang-iat
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RayWang-iat
changed the title
Oceania2018
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Jun 2, 2023
| var x1 = new NDArray(new[,] { { 1, 2, 3 }, { 4, 5.1, 6 } }); | ||
| var x2 = new NDArray(new[,] { { 3, 2, 1 }, { 6, 5.1, 4 } }); | ||
| var y = np.maximum(x1,x2); | ||
| var y1 = np.maximum(x1, x2, axis: 0); |
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Thanks for your contribution.
Can you add one more testing case
np.maximum(x1, x2, axis: 1)
Oceania2018
approved these changes
Jun 5, 2023
| var y3 = new NDArray(new[,] { { 3, 2, 3 }, { 6, 5.1, 6 } }); | ||
| var y4 = new NDArray(new[] { 6, 5.1, 6 }); | ||
| var y5 = new NDArray(new[] { 3.0, 6 }); | ||
| Assert.AreEqual(y0, y3); |
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We can use the simplier syntax like: Assert.AreEqual(new[,] { { 3, 2, 3 }, { 6, 5.1, 6 } }, y0.numpy());
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Solve the problem that NDArray.max() does not support max from multiple dimensions and add a TestMethod. #635
And the NDArray.sum() method has already supported max from multiple dimensions.
Thanks!