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| 1 | +using SciMLNLSolve, SciMLBase |
| 2 | + |
| 3 | +# IIP Tests |
| 4 | +function f_iip(du, u, p, t) |
| 5 | + du[1] = 2 - 2u[1] |
| 6 | + du[2] = u[1] - 4u[2] |
| 7 | +end |
| 8 | +u0 = zeros(2) |
| 9 | +prob_iip = SteadyStateProblem(f_iip, u0) |
| 10 | +abstol = 1e-8 |
| 11 | + |
| 12 | +for alg in [NLSolveJL()] |
| 13 | + sol = solve(prob_iip, alg) |
| 14 | + @test sol.retcode == :Success |
| 15 | + p = nothing |
| 16 | + |
| 17 | + du = zeros(2) |
| 18 | + f_iip(du, sol.u, nothing, 0) |
| 19 | + @test maximum(du) < 1e-6 |
| 20 | +end |
| 21 | + |
| 22 | +# OOP Tests |
| 23 | +f_oop(u, p, t) = [2 - 2u[1],u[1] - 4u[2]] |
| 24 | +u0 = zeros(2) |
| 25 | +prob_oop = SteadyStateProblem(f_oop, u0) |
| 26 | + |
| 27 | +for alg in [NLSolveJL()] |
| 28 | + sol = solve(prob_oop, alg) |
| 29 | + @test sol.retcode == :Success |
| 30 | + |
| 31 | + du = zeros(2) |
| 32 | + du = f_oop(sol.u, nothing, 0) |
| 33 | + @test maximum(du) < 1e-6 |
| 34 | +end |
| 35 | + |
| 36 | +# NonlinearProblem Tests |
| 37 | + |
| 38 | +function f_iip(du, u, p) |
| 39 | + du[1] = 2 - 2u[1] |
| 40 | + du[2] = u[1] - 4u[2] |
| 41 | +end |
| 42 | +u0 = zeros(2) |
| 43 | +prob_iip = NonlinearProblem{true}(f_iip, u0) |
| 44 | +abstol = 1e-8 |
| 45 | +for alg in [NLSolveJL()] |
| 46 | + local sol |
| 47 | + sol = solve(prob_iip, alg) |
| 48 | + @test sol.retcode == :Success |
| 49 | + p = nothing |
| 50 | + |
| 51 | + du = zeros(2) |
| 52 | + f_iip(du, sol.u, nothing) |
| 53 | + @test maximum(du) < 1e-6 |
| 54 | +end |
| 55 | + |
| 56 | +# OOP Tests |
| 57 | +f_oop(u, p) = [2 - 2u[1],u[1] - 4u[2]] |
| 58 | +u0 = zeros(2) |
| 59 | +prob_oop = NonlinearProblem{false}(f_oop, u0) |
| 60 | +for alg in [NLSolveJL(),] |
| 61 | + local sol |
| 62 | + sol = solve(prob_oop, alg) |
| 63 | + @test sol.retcode == :Success |
| 64 | + |
| 65 | + du = zeros(2) |
| 66 | + du = f_oop(sol.u, nothing) |
| 67 | + @test maximum(du) < 1e-6 |
| 68 | +end |
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