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Account for move error in the spread operator on struct literals
We attempt to suggest an appropriate clone for move errors on expressions
like `S { ..s }` where a field isn't `Copy`. If we can't suggest, we still don't
emit the incorrect suggestion of `S { ..s }.clone()`.
```
error[E0509]: cannot move out of type `S<K>`, which implements the `Drop` trait
--> $DIR/borrowck-struct-update-with-dtor.rs:28:19
|
LL | let _s2 = S { a: 2, ..s0 };
| ^^^^^^^^^^^^^^^^
| |
| cannot move out of here
| move occurs because `s0.c` has type `K`, which does not implement the `Copy` trait
|
help: clone the value from the field instead of using the spread operator syntax
|
LL | let _s2 = S { a: 2, c: s0.c.clone(), ..s0 };
| +++++++++++++++++
```
```
error[E0509]: cannot move out of type `S<()>`, which implements the `Drop` trait
--> $DIR/borrowck-struct-update-with-dtor.rs:20:19
|
LL | let _s2 = S { a: 2, ..s0 };
| ^^^^^^^^^^^^^^^^
| |
| cannot move out of here
| move occurs because `s0.b` has type `B`, which does not implement the `Copy` trait
|
note: `B` doesn't implement `Copy` or `Clone`
--> $DIR/borrowck-struct-update-with-dtor.rs:4:1
|
LL | struct B;
| ^^^^^^^^
help: if `B` implemented `Clone`, you could clone the value from the field instead of using the spread operator syntax
|
LL | let _s2 = S { a: 2, b: s0.b.clone(), ..s0 };
| +++++++++++++++++
```
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