Merge pull request #1322 from steffahn/assigment

Fix typo “assigment” (…and more)

Author: ehuss

src/expressions/if-expr.md

@@ -129,7 +129,7 @@ The expression cannot be a [lazy boolean operator expression][_LazyBooleanOperat
 Use of a lazy boolean operator is ambiguous with a planned feature change of the language (the implementation of if-let chains - see [eRFC 2947][_eRFCIfLetChain_]).
 When lazy boolean operator expression is desired, this can be achieved by using parenthesis as below:
 
-<!-- ignore: psuedo code -->
+<!-- ignore: pseudo code -->
 ```rust,ignore
 // Before...
 if let PAT = EXPR && EXPR { .. }

src/expressions/operator-expr.md

@@ -600,7 +600,7 @@ It will then set the value of the assigned operand's place to the value of perfo
 
 > **Note**: This is different than other expressions in that the right operand is evaluated before the left one.
 
-Otherwise, this expression is syntactic sugar for calling the function of the overloading compound assigment trait of the operator (see the table earlier in this chapter).
+Otherwise, this expression is syntactic sugar for calling the function of the overloading compound assignment trait of the operator (see the table earlier in this chapter).
 A mutable borrow of the assigned operand is automatically taken.
 
 For example, the following expression statements in `example` are equivalent:

src/patterns.md

@@ -429,7 +429,7 @@ The bounds can be literals or paths that point to constant values.
 
 A half open range with only an upper bound is written as `..=` followed by its upper bound.
 These range patterns will match on any value less than or equal to the upper bound.
-For example, `..=10` will match 10, 1, 0, and for signed interger types, all negative values.
+For example, `..=10` will match 10, 1, 0, and for signed integer types, all negative values.
 
 Half-open range patterns cannot be used as the top-level pattern for subpatterns in [slice patterns](#slice-patterns).