types typescript does not work when using the spread operator

[anzor1qqqqq]

🔎 Search Terms

types typescript, spread operator

🕗 Version & Regression Information

in all version typscript

⏯ Playground Link

https://www.typescriptlang.org/play/?#code/MYewdgzgLgBAZgSwE7RgXhgbwLACgYEwCGA5gKYBcMATNXgL556iSxFU76FhEC2lMaEgRgSDdFjyEYAOjmIUUADRTufAQHIiYAF4gkGhkA

💻 Code

const first = {
age: 22
}

const a: {
name: string
} = {
...first,
name: 'anzor'
}

🙁 Actual behavior

the compiler does not cause an error in the second object type

🙂 Expected behavior

the ts compiler should warn about the type mismatch

Additional information about the issue

No response

[MartinJohns]

Duplicate of #39998. Excess property checks are not performed when spreading.

There is no type mismatch. Additional properties are allowed to exist on objects.

[anzor1qqqqq]

Duplicate of #39998. Excess property checks are not performed when spreading.

There is no type mismatch. Additional properties are allowed to exist on objects.

How can this be defeated??????????

[MartinJohns]

It's a fundamental part of TypeScripts type system, it's intentional.

[typescript-bot]

This issue has been marked as "Duplicate" and has seen no recent activity. It has been automatically closed for house-keeping purposes.