keyof does not work for computed property name of getter or setter

[upsuper]

🔎 Search Terms

keyof get computed name

🕗 Version & Regression Information

• This is the behavior in every version I tried, and I reviewed the FAQ for entries about _________

⏯ Playground Link

https://www.typescriptlang.org/play?ts=5.4.0-dev.20231226#code/C4TwDgpgBAYg9nAPAFShAHsCA7AJgZygG8BfAPigF5iAoKeqAJwgENc5sAbEKAbQGkoAS2xQA1hBBwAZlGQBdAFxR8wRiIDmAbhokdNUJCgAhFoxRpMOAsXJVaDKBojA+gkeMky58gBQBKZVV1bG1dLSA

💻 Code

// This works.
type Foo<T extends {}> = {
    readonly [K in keyof T]: string;
};

// This doesn't.
type Bar<T extends {}> = {
    get [K in keyof T](): string;
};

🙁 Actual behavior

Bar doesn't compile. The compiler says:

A computed property name must be of type 'string', 'number', 'symbol', or 'any'.
Property '[K in keyof' implicitly has type 'any', because its get accessor lacks a return type annotation.

🙂 Expected behavior

Both type declarations above should work in the same way.

Additional information about the issue

No response

[upsuper]

I think this is a duplicate of #51890.