-
Notifications
You must be signed in to change notification settings - Fork 12.9k
Open
Labels
BugA bug in TypeScriptA bug in TypeScriptFix AvailableA PR has been opened for this issueA PR has been opened for this issue
Milestone
Description
Cannot assign generic type aliases that should be equivalent.
Simple test case:
export type Example<TData>
= (data: TData | null | undefined) => string | null;
function foo<T>()
{
let x: Example<T> = undefined!;
let y: Example<T | null | undefined> = undefined!;
y = x;
let x1: (data: T | null | undefined) => string | null = undefined!;
let y1: (data: (T | null | undefined) | null | undefined) => string | null = undefined!;
y1 = x1
}
Note that 'x' is not assignable to 'y' with strictNullChecks
on. It results in the error:
Type 'Example<T>' is not assignable to type 'Example<T | null | undefined>'.
Type 'T | null | undefined' is not assignable to type 'T'.
'T' could be instantiated with an arbitrary type which could be unrelated to 'T | null | undefined'.
Type 'undefined' is not assignable to type 'T'.
'T' could be instantiated with an arbitrary type which could be unrelated to 'undefined'.(2322)
This seems very strange though. Example
is just a type alias, which shouldn't have an impact on assignability. If we simply expand the type alias, we get the x1/y1
case. In the expanded form the compiler allows this just fine.
Note: this was working in 3.3. It does not seem to work on 4.0. I'm not sure at what point it may have broken.
Ed-zo
Metadata
Metadata
Assignees
Labels
BugA bug in TypeScriptA bug in TypeScriptFix AvailableA PR has been opened for this issueA PR has been opened for this issue