Prepending true || confuses strict null checks, even with correct bracketing

[robinmessage]

OR-ing an expression which passes type checking with true causes that expression to fail type checking.

TypeScript Version: 3.6.0-dev.20190611

Search Terms: boolean logic strict null check confused or with true

Code

type Foo = { bar?: { baz?: string } };
const foo = (something: Foo) => (something.bar && something.bar.baz);
const quux = (something: Foo) => true || (something.bar && something.bar.baz);

Expected behavior:
foo and quux both pass type checking with strict null checks.

Actual behavior:
foo is fine, but tsc complains about something.bar.baz in quux. It is almost like it interprets it as (true || something.bar) && something.bar.baz which would indeed be unsafe.

Playground Link: https://www.typescriptlang.org/play/#src=type%20Foo%20%3D%20%7B%20bar%3F%3A%20%7B%20baz%3F%3A%20string%20%7D%20%7D%3B%0D%0Aconst%20foo%20%3D%20(something%3A%20Foo)%20%3D%3E%20(something.bar%20%26%26%20something.bar.baz)%3B%0D%0Aconst%20quux%20%3D%20(something%3A%20Foo)%20%3D%3E%20true%20%7C%7C%20(something.bar%20%26%26%20something.bar.baz)%3B%0D%0A
— N.B. it only fails with strict null checks turned on

Related Issues: I did not find any.

[nmain]

Duplicate of #26914

[robinmessage]

Thanks, it didn't occur to me that the code was unreachable and that was why it didn't work, so I didn't see the other ticket.