do not use base name of the directory as module name

Run "go build ./x" in this workspace:

  -- go.work --
  use ./y
  -- x/go.mod --
  module x

  go 1.19
  -- x/m.go --
  package m

It fails with: "go: open /tmp/foo/y/go.mod: no such file or directory".
It's unclear where the name "y" comes from.
This change will emit error like: "go: cannot load module added to
go.work file: open /tmp/foo/y/go.mod: no such file or directory"

Author: ZekeLu

src/cmd/go/internal/modload/init.go

@@ -719,7 +719,7 @@ func LoadModFile(ctx context.Context) *Requirements {
 		data, f, err := ReadModFile(gomod, fixVersion(ctx, &fixed))
 		if err != nil {
 			if inWorkspaceMode() {
-				base.Fatalf("go: cannot load module %s named in go.work file: %v", filepath.Base(modroot), err)
+				base.Fatalf("go: cannot load module added to go.work file: %v", err)
 			} else {
 				base.Fatalf("go: %v", err)
 			}

src/cmd/go/testdata/script/work_use_issue55952.txt

@@ -1,5 +1,5 @@
 ! go list .
-stderr '^go: cannot load module y named in go\.work file: open .+go\.mod: no such file or directory$'
+stderr '^go: cannot load module added to go\.work file: open .+go\.mod: no such file or directory$'
 
 -- go.work --
 use ./y