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| 1 | +// Copyright 2023 The Go Authors. All rights reserved. |
| 2 | +// Use of this source code is governed by a BSD-style |
| 3 | +// license that can be found in the LICENSE file. |
| 4 | + |
| 5 | +package p |
| 6 | + |
| 7 | +func f[T any](...T) T { var x T; return x } |
| 8 | + |
| 9 | +// Test case 1 |
| 10 | + |
| 11 | +func _() { |
| 12 | + var a chan string |
| 13 | + var b <-chan string |
| 14 | + f(a, b) |
| 15 | + f(b, a) |
| 16 | +} |
| 17 | + |
| 18 | +// Test case 2 |
| 19 | + |
| 20 | +type F[T any] func(T) bool |
| 21 | + |
| 22 | +func g[T any](T) F[<-chan T] { return nil } |
| 23 | + |
| 24 | +func f1[T any](T, F[T]) {} |
| 25 | +func f2[T any](F[T], T) {} |
| 26 | + |
| 27 | +func _() { |
| 28 | + var ch chan string |
| 29 | + f1(ch, g("")) |
| 30 | + f2(g(""), ch) |
| 31 | +} |
| 32 | + |
| 33 | +// Test case 3: named and directional types combined |
| 34 | + |
| 35 | +func _() { |
| 36 | + type namedA chan int |
| 37 | + type namedB chan<- int |
| 38 | + |
| 39 | + var a chan int |
| 40 | + var A namedA |
| 41 | + var b chan<- int |
| 42 | + var B namedB |
| 43 | + |
| 44 | + // Defined types win over channel types irrespective of channel direction. |
| 45 | + f(A, b /* ERROR "cannot use b (variable of type chan<- int) as namedA value in argument to f" */) |
| 46 | + f(b /* ERROR "cannot use b (variable of type chan<- int) as namedA value in argument to f" */, A) |
| 47 | + |
| 48 | + f(a, b /* ERROR "cannot use b (variable of type chan<- int) as namedA value in argument to f" */, A) |
| 49 | + f(a, A, b /* ERROR "cannot use b (variable of type chan<- int) as namedA value in argument to f" */) |
| 50 | + f(b /* ERROR "cannot use b (variable of type chan<- int) as namedA value in argument to f" */, A, a) |
| 51 | + f(b /* ERROR "cannot use b (variable of type chan<- int) as namedA value in argument to f" */, a, A) |
| 52 | + f(A, a, b /* ERROR "cannot use b (variable of type chan<- int) as namedA value in argument to f" */) |
| 53 | + f(A, b /* ERROR "cannot use b (variable of type chan<- int) as namedA value in argument to f" */, a) |
| 54 | + |
| 55 | + // Unnamed directed channels win over bidirectional channels. |
| 56 | + b = f(a, b) |
| 57 | + b = f(b, a) |
| 58 | + |
| 59 | + // Defined directed channels win over defined bidirectional channels. |
| 60 | + A = f(A, a) |
| 61 | + A = f(a, A) |
| 62 | + B = f(B, b) |
| 63 | + B = f(b, B) |
| 64 | + |
| 65 | + f(a, b, B) |
| 66 | + f(a, B, b) |
| 67 | + f(b, B, a) |
| 68 | + f(b, a, B) |
| 69 | + f(B, a, b) |
| 70 | + f(B, b, a) |
| 71 | + |
| 72 | + // Differently named channel types conflict irrespective of channel direction. |
| 73 | + f(A, B /* ERROR "type namedB of B does not match inferred type namedA for T" */) |
| 74 | + f(B, A /* ERROR "type namedA of A does not match inferred type namedB for T" */) |
| 75 | + |
| 76 | + // Ensure that all combinations of directional and |
| 77 | + // bidirectional channels with a named directional |
| 78 | + // channel lead to the correct (named) directional |
| 79 | + // channel. |
| 80 | + B = f(a, b) |
| 81 | + B = f(a, B) |
| 82 | + B = f(b, a) |
| 83 | + B = f(B, a) |
| 84 | + |
| 85 | + B = f(a, b, B) |
| 86 | + B = f(a, B, b) |
| 87 | + B = f(b, B, a) |
| 88 | + B = f(b, a, B) |
| 89 | + B = f(B, a, b) |
| 90 | + B = f(B, b, a) |
| 91 | + |
| 92 | + // verify type error |
| 93 | + A = f /* ERROR "cannot use f(B, b, a) (value of type namedB) as namedA value in assignment" */ (B, b, a) |
| 94 | +} |
| 95 | + |
| 96 | +// Test case 4: some more combinations |
| 97 | + |
| 98 | +func _() { |
| 99 | + type A chan int |
| 100 | + type B chan int |
| 101 | + type C = chan int |
| 102 | + type D = chan<- int |
| 103 | + |
| 104 | + var a A |
| 105 | + var b B |
| 106 | + var c C |
| 107 | + var d D |
| 108 | + |
| 109 | + f(a, b /* ERROR "type B of b does not match inferred type A for T" */, c) |
| 110 | + f(c, a, b /* ERROR "type B of b does not match inferred type A for T" */) |
| 111 | + f(a, b /* ERROR "type B of b does not match inferred type A for T" */, d) |
| 112 | + f(d, a, b /* ERROR "type B of b does not match inferred type A for T" */) |
| 113 | +} |
| 114 | + |
| 115 | +// Simplified test case from issue |
| 116 | + |
| 117 | +type Matcher[T any] func(T) bool |
| 118 | + |
| 119 | +func Produces[T any](T) Matcher[<-chan T] { return nil } |
| 120 | + |
| 121 | +func Assert1[T any](Matcher[T], T) {} |
| 122 | +func Assert2[T any](T, Matcher[T]) {} |
| 123 | + |
| 124 | +func _() { |
| 125 | + var ch chan string |
| 126 | + Assert1(Produces(""), ch) |
| 127 | + Assert2(ch, Produces("")) |
| 128 | +} |
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