1480-Running-Sum-of-1d-Array.py

'''
Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).

Return the running sum of nums.
'''
class Solution:
    def runningSum(self, nums: List[int]) -> List[int]:
        ans = []
        tmp = 0
        for i in range(len(nums)):
            tmp += nums[i]
            ans.append(tmp)
        
        return ans