Given an integer array nums, rotate the array to the right by k steps, where k is non-negative.
Input: nums = [1,2,3,4,5,6,7], k = 3
Output: [5,6,7,1,2,3,4]
Explanation: rotate 1 steps to the right: [7,1,2,3,4,5,6]
rotate 2 steps to the right: [6,7,1,2,3,4,5]
rotate 3 steps to the right: [5,6,7,1,2,3,4]Input: nums = [-1,-100,3,99], k = 2
Output: [3,99,-1,-100]
Explanation: rotate 1 steps to the right: [99,-1,-100,3]
rotate 2 steps to the right: [3,99,-1,-100]1 <= nums.length <= 10⁵-2³¹ <= nums[i] <= 2³¹ - 10 <= k <= 10⁵
const rotate = (nums, k) => {
for (let i = nums.length - 1; i >= 0; i--) {
nums[i + k] = nums[i];
}
for (let j = k - 1; j >= 0; j--) {
nums[j] = nums.pop();
}
};I've written a function called rotate which takes in an array nums and a number k as parameters. The function is used to rotate the elements of the array nums to the right by k positions.
This function consists of two for loops. The first for loop starts from the last index of the array nums and iterates backwards until it reaches the first index. Inside this loop, each element at index i is assigned to the element at index i + k in the array nums. This effectively shifts the elements to the right by k positions.
After the first for loop, the elements of the array nums have been shifted to the right, but the first k elements are duplicates of the original elements.
The second for loop starts from k - 1 and iterates backwards until it reaches 0. Inside this loop, the last element of the array nums is removed using the pop method, and the removed element is assigned to the current element at index j in the array nums. This effectively replaces the duplicate elements at the beginning of the array with the original elements.
Once the second for loop completes, the array nums will contain the elements rotated to the right by k positions.
It's important to note that this function modifies the original array nums in place and does not return a new array.