From b327eac165d3b300d76e348d7fb75bd1dc4a39b2 Mon Sep 17 00:00:00 2001 From: martacarballo Date: Sat, 22 Nov 2025 15:37:13 +0100 Subject: [PATCH] solved --- basic queries.sql | 65 +++++++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 65 insertions(+) create mode 100644 basic queries.sql diff --git a/basic queries.sql b/basic queries.sql new file mode 100644 index 0000000..0d6e491 --- /dev/null +++ b/basic queries.sql @@ -0,0 +1,65 @@ +USE sakila; + +SELECT COUNT(*) FROM film; +SELECT COUNT(*) FROM film_text; +-- 1) display all tables +SHOW FULL TABLES; + +-- 2) Retrieve all the data from the tables actor, film and customer. +SELECT * FROM actor, film, customer; + +/*Retrieve the following columns from their respective tables: + - 3.1 Titles of all films from the `film` table + - 3.2 List of languages used in films, with the column aliased as `language` from the `language` table + - 3.3 List of first names of all employees from the `staff` table*/ +SELECT title FROM film; + +select f.title, l.name as language +from sakila.film f inner join sakila.language l on f.language_id = l.language_id; + +SELECT first_name from staff; + +-- 4 Retrieve unique release years. +SELECT DISTINCT release_year from film + +/* Counting records for database insights: + +5.1 Determine the number of stores that the company has. +5.2 Determine the number of employees that the company has. +5.3 Determine how many films are available for rent and how many have been rented. +5.4 Determine the number of distinct last names of the actors in the database.*/ + +SELECT COUNT(*) from store; +SELECT COUNT(*) from staff; + +-- Asumimos que todas las películas están alquiladas a día de hoy en tabla rental +SELECT + (SELECT COUNT(*) + FROM inventory) AS films_available_for_rent, + (SELECT COUNT(DISTINCT inventory_id) + FROM rental) AS films_rented;inventory + +SELECT COUNT(distinct last_name) from actor; + +-- 6. Retrieve the 10 longest films. +SELECT title, length +FROM film +ORDER BY length DESC +LIMIT 10; + +- +-- 7.1 Retrieve all actors with the first name "SCARLETT". +SELECT * FROM actor WHERE first_name = 'SCARLETT'; + +-- 7.2 Retrieve all movies that have ARMAGEDDON in their title and have a duration longer than 100 minutes. +SELECT * +FROM film +WHERE title LIKE '%ARMAGEDDON%' AND length > 100; + +-- 7.3 Determine the number of films that include Behind the Scenes content +SELECT COUNT(*) +from film +WHERE special_features LIKE '%behind the scenes%' + + +