Create Lab2 Week4.sql

Lab2 Week4.sql

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+-- Use the Sakila database
+USE sakila;
+
+-- 1) Display all available tables
+SHOW TABLES;
+-- (Alternative)
+SELECT TABLE_NAME
+FROM information_schema.TABLES
+WHERE TABLE_SCHEMA = 'sakila'
+ORDER BY TABLE_NAME;
+
+-- 2) Retrieve all data from actor, film, customer
+SELECT * FROM actor;
+SELECT * FROM film;
+SELECT * FROM customer;
+
+-- 3) Specific columns
+-- 3.1 Titles of all films
+SELECT title FROM film ORDER BY title;
+
+-- 3.2 Languages used in films, aliased as 'language'
+SELECT name AS language FROM language ORDER BY language;
+
+-- 3.3 First names of all employees (staff)
+SELECT first_name FROM staff ORDER BY first_name;
+
+-- 4) Retrieve unique release years
+SELECT DISTINCT release_year FROM film ORDER BY release_year;
+
+-- 5) Counting records
+-- 5.1 Number of stores
+SELECT COUNT(*) AS store_count FROM store;
+
+-- 5.2 Number of employees
+SELECT COUNT(*) AS employee_count FROM staff;
+
+-- 5.3 How many films are available for rent vs rented
+-- (A) Total copies available in inventory (all rentable copies in the catalog)
+SELECT COUNT(*) AS total_inventory_copies FROM inventory;
+
+-- (B) Total rentals ever made (how many times copies were rented)
+SELECT COUNT(*) AS total_rentals FROM rental;
+
+-- 5.4 Number of distinct actor last names
+SELECT COUNT(DISTINCT last_name) AS distinct_actor_last_names FROM actor;
+
+-- 6) Retrieve the 10 longest films
+SELECT film_id, title, length
+FROM film
+ORDER BY length DESC, title
+LIMIT 10;
+
+-- 7) Filtering
+-- 7.1 All actors named exactly 'SCARLETT'
+SELECT actor_id, first_name, last_name
+FROM actor
+WHERE first_name = 'SCARLETT'
+ORDER BY last_name, actor_id;