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+# 1. You need to use SQL built-in functions to gain insights relating to the duration of movies:
+# Determine the shortest and longest movie durations
+SELECT 
+    MAX(length) AS max_duration,
+    MIN(length) AS min_duration
+FROM film;
+
+# Express the average movie duration in hours and minutes (no decimals)
+
+SELECT 
+    FLOOR(AVG(length) / 60) AS avg_hours,
+    ROUND(AVG(length) % 60) AS avg_minutes
+FROM film;
+
+
+# 2.You need to gain insights related to rental dates:
+# Number of days the company has been operating
+SELECT 
+    DATEDIFF(MAX(rental_date), MIN(rental_date)) AS days_operating
+FROM rental;
+
+# Retrieve rental info + month and weekday (first 20 rows)
+SELECT 
+    rental_id,
+    rental_date,
+    MONTHNAME(rental_date) AS rental_month,
+    DAYNAME(rental_date) AS rental_weekday
+FROM rental
+LIMIT 20;
+
+# Bonus: Add column DAY_TYPE ('weekend' or 'workday')
+
+SELECT 
+    rental_id,
+    rental_date,
+    DAYNAME(rental_date) AS rental_weekday,
+    CASE 
+        WHEN DAYOFWEEK(rental_date) IN (1, 7) THEN 'weekend'
+        ELSE 'workday'
+    END AS day_type
+FROM rental
+LIMIT 20;
+
+# 3.User-Friendly Movie Info with NULL Handling
+SELECT 
+    title,
+    IFNULL(rental_duration, 'Not Available') AS rental_duration
+FROM film
+ORDER BY title ASC;
+
+# 4. Bonus: Customer Personalization Data for Marketing
+
+SELECT 
+    CONCAT(first_name, ' ', last_name) AS full_name,
+    LEFT(email, 3) AS email_prefix
+FROM customer
+ORDER BY last_name ASC;
+
+# Challenge 2
+
+#1. Total number of films released
+
+SELECT COUNT(*) AS total_films
+FROM film;
+
+#2.Number of films for each rating
+
+SELECT rating, COUNT(*) AS film_count
+FROM film
+GROUP BY rating;
+
+# 3.Number of films for each rating (sorted descending by count)
+
+SELECT rating, COUNT(*) AS film_count
+FROM film
+GROUP BY rating
+ORDER BY film_count DESC;
+
+# 2. Film Duration Analysis by Rating
+SELECT 
+    rating,
+    ROUND(AVG(length), 2) AS avg_duration
+FROM film
+GROUP BY rating
+ORDER BY avg_duration DESC;
+
+# Ratings with mean duration over 2 hours (120 minutes)
+
+SELECT 
+    rating,
+    ROUND(AVG(length), 2) AS avg_duration
+FROM film
+GROUP BY rating
+HAVING AVG(length) > 120
+ORDER BY avg_duration DESC;
+
+# Bonus: Unique Last Names in the actor Table
+SELECT last_name
+FROM actor
+GROUP BY last_name
+HAVING COUNT(*) = 1;
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